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1. 2;

Interest earned under default plan III = Rs. 3762

Interest rate of plan I = 11%

Interest earned under plan III at 11% p.a. compounded

annually

= 20000 (1 + 11/100)^2 – 20000 = Rs. 4642

Difference in interest earned = 4642 – 3762 = Rs. 880 more

2. 1
Original term is 12 and when it is tripled it becomes 36 months

Interest on Rs. 45,000 @ 12.50% p.a (compounded annually) for 36 months is

= 45000 (1 + 12.5/100)^3 – 45000 = 19072.27

3. 3
Maturity amount of plan II = 35000 + 6562.5 = Rs. 41562.5

Rs. 41562.5 deposited for 2 years in plan I gives = [ 1 + (2 * 11)/100 ] * 41562.5 = Rs. 50706.25

4. 4
Interest earned under plan III (Compounded annually) = Rs. 3762

Interest earned under plan III (If the interest is not compounded) = (20000 * 2 * 9)/100 = Rs. 3600

Required ratio = 3762 : 3600 = 209 : 200

5. 4
Investment of Rs. 45000 in plan will earn in 24 months

= 45000 ( 1 + 12.5/100)^2 – 45000 = Rs. 11953.125

6. 3
Total weight of J, K and L = 75 × 3 = 225 kg

Total weight of J, K, L and M = 78 × 4 = 312 kg

Weight of M = 312 – 225 = 87 kg

Weight of N = 87 – 5 = 82 kg

Total weight of K, L, M & N = 77 × 4 = 308 kg

Total weight of K, L & M = 308 – 82 = 226 kg

Weight of J = weight of (J, K, L and M) – weight of (K,

L and M)

= 312 – 226 = 86 kg

7. 1
Required number of ways = 6C4 × 5C2 = 6*5/2 * 5*4/2 = 150

8. 4
1st person, 2ndperson, 5th person, 10th person, 25th

person & 50th person will put balls in the 50th bucket.

So number of balls in the 50th bucket

= 1 + 2 + 5 + 10+ 25 + 50 = 93

9. 1
Ten years ago, total age of four members = 28 × 4 = 112 years

Total age of four members at present = (28 + 10) ×4 = 152 years

And present age of four members + two children = 28 × 6 = 168 years

So age of the two children = 168 – 152 =16

So age of 1st child = 9 years

And age of 2nd child= 7 years

10. 1;
Let total number of candidates be = 100
Number of candidates who took both German and English = (76.5 + 48.7) – 100 = 25.2

i.e. 100 units —> 3250

25.2 units —> 3250/100 * 25.2 = 819

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