**I. Study the following graph carefully to answer the given questions**

**P and R started the work jointly. A few days later U also joined them and thus all of them completed the whole work in 10 days. All of them were paid total Rs.600. What is the Share of U?**

A. Rs.360

B. Rs.385

C. Rs.240

D. can’t be determined

E. None of these
Answer & Explanation

Answer – **C. Rs.240**

**Explanation :**

Efficiency of P = 4%

Efficiency of R = 2%

[(4+2)*10] = 60%

The remaining work was done by U = 40%.

40% of 600 = 240

**Q and S work together for 5 days, the rest of the work is finished by M in two more days. If they get Rs. 6000 as wages for the whole work, what are the daily wages of Q, S and M respectively?**

A. 200, 250, 300

B. 300, 200, 250

C. 600, 400, 200

D. 600, 400, 500

E. None of these
Answer & Explanation

**Answer – D. 600, 400, 500**

**Explanation :**

Explanation:

Q’s 5 days work = 50%

S’s 5 days work = 33.33%

M’s 2 days work = 16.66% [100- (50+33.33)] Ratio of work of Q, S and M = 3: 2: 1

Q’s total share = Rs. 3000

S’s total share = Rs. 2000

M’s total share = Rs. 1000

Q’s one day’s wage = Rs.600

S’s one day’s wage = Rs.400

M’s one day’s wage = Rs.500

**The efficiency of L is 25% more than P. L started a work alone and then P joined her 5 days before actual completion of the work. For how many days L worked alone?**

A. 9

B. 11

C. 10

D. 25

E. 12
Answer & Explanation

**Answer – B. 11**

**Explanation :**

Efficiency (L : P) = 5 : 4

Number of days(L : P) = 4x : 5x = 4x : 25

∴ Number of days required by L to finish the work alone = 4x

= 4 x 5 = 20.

L and P work together for last 5 days = 5 x 9 = 45%

Efficiency of L = 5% and P’s efficiency = 4%

∴ No. of days taken by L to complete 55% work = 55/5 = 11days

**R started the work and left after some days, when 25% work was done. After it Z joined and completed it working for 25 days. In how many days R and Z can do the complete work, working together?**

A. 6

B. 8

C. 10

D. 12

E. 20
Answer & Explanation

**Answer – E. 20**

**Explanation :**

Efficiency of R = (100/50) = 2%

Rest work = 75%

∴ Efficiency of Z = 75/25 = 3%

∴ Combined efficiency of R and Z = 5%

∴ Number of days required by R and Z to work together = 100/5 = 20 days.

**T and V started the work. After 3 days Z joined them, who can complete alone the same whole work in 3 days. What is the total number of days in which they had completed the work?**

A. 12

B. 8

C. 4

D. 6

E. None of these
Answer & Explanation

Answer – **C.4 days**

**Explanation :**

Efficiency of T and V = 11.11 + 5.55 = 16.66%

Work done in 3 days = 3 x 16.66 = 50%

Rest work done by T, V and Z = 50/50 = 1 day

Work can be completed in 4 days.

**A is twice efficient as B and together they do the same work in as much time as T and V together. In how many days A can complete the work individually?**

A. 5 days

B. 8 days

C. 4 days

D. 9 days

E. None of these
Answer & Explanation

Answer – **D. 9 days**

**Explanation :**

1/x + 1/2x = 1/9 + 1/18

3/2x = 3/18

Number of days taken by A = 9 days

**After working for 3 days S is joined by O. If they complete the remaining work in 3 more days, in how many days can O alone complete the work?**

A. 10 days

B. 8 days

C. 5 days

D. 12 days

E. 15 days
Answer & Explanation

Answer – **C. 5 days**

**Explanation :**

Total days S worked = 3+3 = 6

6/15 = 2/5

So 3/5 = 3/x

x = 5

**M can do a piece of work 5 days less than that of P. M and P began to work together but M**** leaves after some days and P completed the remaining work in 12 days. Number of days after which M left the job-**

A. 5.7/9 days

B. 6.7/9 days

C. 7.7/9 days

D. 11.7/9 days

E. None of these
Answer & Explanation

Answer –** A. 5.7/9 days**

**Explanation :**

(1/20 + 1/25)*T + 12/25 = 1

We will get T = 52/9 i.e. 5.7/9 days

**X can do a certain work in the same time in which Y and R together can do it. If X and Y together could do it in the same time as that of Q then Y alone could do it in:**

A. 15 days

B. 20 days

C. 25 days

D. 30 days

E. 35 days
Answer & Explanation

Answer – **C.25 days**

**Explanation :**

X, Y and R’s 1 day work = 1/10 + 1/50 = 6/50 = 3/25

X’s 1 day work = Y + R‘s 1 day work

2*( x’s 1 day work) = 3/25

x’s 1 day work = 3/50

Y’s 1 day work = 1/10 – 3/50 = 2/50 = 1/25

**A can do a piece of work 10 days more than that of Q. Both of them start the work but A leaves the work 5 days before its completion. Find the time in which work is completed**

A. 10

B. 15

C. 20

D. 25

E. None of these
Answer & Explanation

Answer – **A. 10**

**Explanation :**

(1/10 + 1/20)*(T-5) + 5/20 = 1 (T is the number of days in which the work is completed)

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