*SSC CGL Study Material Book Free PDF >> Download Now*

Quant Booster – A Complete Maths Shortcut Book (850+ Pages) |
Get Now |

Download Reasoning General Intelligence Power Book (1200+ Pages) |
Free Download Now |

**Answers :-**

*1. (c) LCM × HCF = 1st. Number × 2nd. number or**Product of numbers = HCF × LCM**→ LCM = 864**HCF = 144**One number x = 288**Thus Let other no. be y**Thus,, x y = LCM × HCF**→ 288 × y = 864 × 144**y =**= 432**Thus, Other no. will be = 432*

*2. (c) LCM = 225**HCF = 5**One number = 25**Thus, Let other number be y**Thus,. 25 × y = 225 × 5**y =**Thus, Another no. is 45*

*3. (c) LCM = 30**HCF = 5 (given)**One number = 10**Let another number = y**Thus, 10y = 30 × 5**y = 15*

*4. (b) HCF = 13**LCM = 455**Thus, Let number be 13x & 13y**Thus, LC M = 13 × y**Thus, LCM = HCF × Product of other factor**13 x y = 455**xy =**→ x y = 35**Possible co-prime Factors of x,y**→ (35, 1) (5, 7)**Thus, Numbers may be**→ 35 × 13, 1 × 13 = (455, 13)**or**→ 5 × 13, 7 × 13 = (65, 91)**→ But it is given that one number lies between**(75 & 125) so.**→ Numbers are (65, 91) and number between 75**& 125 is 91.**LCM of (65, 91) and number between 75 & 125**is 91.*

*5.**(c) LCM of (4, 6 , 8 , 12, 16)**→ 16 × 3 = 48**Thus, The number when divided by (4, 6 , 8 , 12,**16) leaves reminder 2 is = 48 + 2 = 50*

*6. (d) LCM of (12, 15, 20, 54)**→ 4 × 3 × 5 × 9 = 540**Thus, the required number is**540 + 4 = 544**→ Because when divided by LCM each is divided**completely, By adding 4 in LCM leaves remainder**4.*

*7. (a) 1001 pens, 910 pencils (given)**HCF of 1001, 910 is = 91**Thus, maximum no. of students are = 91*

*8. LCM of 4 , 6 , 8, 14 = 168 seconds**2 4 , 6, 8 , 14**2 2, 3, 4, 7**1, 3. 2 , 7**LCM = 3 × 2 × 7 × 2 × 2 = 168 seconds**= 2 minute 48 seconds**Thus, 1st they start ringing at 12.00 o’clock**→ Again they ring all together after 2 minutes 48**seconds at 12 hrs. 2 min. 48 seconds.*

*9. (a) LCM × HCF = 24**Thus, Product of numbers = 24**Let no. be = x, y**xy = 24**and x – y = 2 (given)**Factors of x y = 24 are (4, 6) (12, 2)**(8, 3) (24, 1)**→ Now difference between numbers be = (x- y)**= 2**So, Factor is (4, 6)*

*10.**(a) LCM = 495**HCF = 5 (given)**Thus, Let numbers are = 5x & 5y**Thus, LCM = 5 x y**5 x y = 495**x y = 99**thus, Possible co-prime factors are**1 , 99**9 , 11**Thus, Possible numbers are**5x , 5y = 45, 55**5, 495**Now, given that sum of numbers = 100**so, required numbers are = (45, 55)**Thus, Difference of numbers = 55 – 45 = 10*