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1. (a) 33.33%

Let B sell at 100

R will sell at 80

120% of C = 80

C= 80*100/120 = 400/6 = 66(2/3).

B-C = 33(1/3)

C is cheaper than B’s by 33(1/3)*100/100 =33.33%

2. (c) Rs. 22,500/-

Suppose his initial capital was 100.

Now, ATQ at the end of 1 year he is left with :-

100——–>150(with profit)——->75(aftr donation)

Similarly after 2nd year:-

75———-> 112.5——->56.25

3rd year:-

56.25——->84.375—–>42.1875

Now, 42.1875 is the amount he is left with after 3 years

but, Given amount = 16,875

Hence, Amount he had after second year :-

42.1875/56.25 = 16875/X

X = 16875*56.25/42.1875 = 22,500

3. Total characters in report = 25*60*75.

Let the new number of pages be ‘x’.

ATQ :-

x*55*90 = 25*60*75

x= 22.72

Therefore, Her report will now require 23 pages.

Drop = 25-23 = 2

Drop% = 2*100/25 = 8%

4. (c) 15,00,000

Let total Population be 300

The, Males population will be 200

Females = 100

As the ratio never changed between males and females. therefore,

100—–>90——>81——>72.9

Now, 72.9 : 364500 : : 300: X

X = 364500*300/72.9 = 5000*300 = 15,00,000.

5. (a) 17%

Let the initial price of Raw materials be 100.

Also, Labour cost earlier was 25.

Total cost earlier = 125

Now after increase,

Raw material = 115

Also, Labour = 30% of 115 = 34.5

Total cost after increase = 115+34.5 = 149.5

So, required reduction = 149.5 – 125 = 24.5

% reduction = 24.5*100/149.5 = 16.38% or 17% approx

6. (b) 1200

ATQ :-

Pased all section = 5%

Passed None = 5%

remaining = 90%

Passed 1 section = 25% of 90% = 22.5%

Passed 4 sections = 20% of 90% = 18%

Passed 2 sections = 24.5%

Passed 3 sections = 300

But passed 3 = 100-(All+1+2+4+none)% = 100-(5+5+22.5+18+24.5) = 25%

25% = 300

100% = 300*100/25 = 1200.

7. (b) Rs. 262

18Km in 1 litre

2400km ———–2400*1/18 = 133.33 litres of petrol every month.

Increase in Expenditure = 133.33*0.07*28 = 261.33 or 262 (Approx.)

8. (d) 55440

Let the population be 100

100—->110——>110*3/4—–>(330/4)*1.05 = 86.625

Now, 100——————–>64000

86.625 = 640*86.625 = 55440.

9. (d) 45

40% conatins two or more people, therefore 60% houses will contain one people.

Now, 25% of 60% is males. therefore, females = 75% of 60%

Females% =75% of 60% = 3*60/4 = 45%

10. (e)

Let the third number be 100.

Hence, First number = 50 and

Second number = 100 – 54 = 46

Decrease = 50 – 46 = 4

Required Percentage = (4/50) x 100 = 8%