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# Solution to the quiz

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1. Option C
→ No. of illiterate female from village B = 60 % (700) = 420
→ No. of illiterate from village B= (9/20)* 2000 = 900
Therefore,
→ No. of illiterate male from village B= 900- 420 =480
→ No. of male from village B = 65 %( 2000) = 1300
→ % of male, who is illiterate from village B = (480/1300) * 100 = 36.9 ≈ 37 (ans)

2. Option B
→ No. of Literate from village A = (2/5)*750 = 300
→ No. of Literate from village B = (11/20)*2000 = 1100
→ No. of Literate from village C = (13/15)*1500 = 1300
→ No. of Literate from village D = (4/5)*2750 = 2200
→ No. of Literate from village E = (1/4)*2500 = 625
→ No. of Literate from village F = (11/30)*3000 = 1100
→ Total no. of literate in all villages= 300+1100+1300+2200+625+1100 = 6,625
→ Total no. of people in all villages= 750+2000+1500+2750+2500+1100 =12,500
→ % of literate people in all villages = (6,625/12,500)* 100 = 53 % (ans)

3. Option C
→ Illiterate from village B= 2000-1100 =900
→ Illiterate from village C=1500-1300 =200
→ Illiterate from village D= 2750-2200 =550
→ Female from village A= 48% (750) = 360
→ Female from village E= 61% (2500) = 1525
→ Female from village F= 25% (3000) = 750
→ Ratio = (900+200+550) : (360 + 1525+750) = 1650 : 2635 = 330 : 527 (ans)

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4. Option D
→ Since we don’t have enough data for village F
→ We cannot determine the answer

5. Option A
→ Female from village A= 360
→ Female from village C = 825
→ Total = 1185
→ Female from village D= 825
→ Female from village F= 750
→ Total= 1575
→ Less% = [(1575 – 1185) /1575] * 100 = (390/1575)* 100
= 24.76 % (ans)

6. Option C
→ No. of students cleared from Maths department = (60/360) * 847 = 141
→ No. of students appeared from English department = (27/ 100)* 5484 ≈ 1481
→ Difference = 1481-141 = 1340 (ans)

7. Option D
→ No. of students cleared from commerce & other dept. = [(72+67) /360]*847 = (139/360)* 847 = 327
→ No. of students cleared physics department = (42/360)* 847 = 99
→ X= (327/99)* 100
→ X= 330 % (ans)

8. Option C
→ Ratio = (Maths +Physics): (Chemistry + Commerce) = (18+14): (11+23) = 32: 34 = 16:17 (ans)

9. Option A
English Department:
→ Appeared = (27/100) * 5484 = 1481
→ Cleared = (88/360)* 847=207
→ Difference = (1485-207) = 1274
Maths Department:
→ Appeared = (18/100) * 5484 = 987
→ Cleared = (60/360)* 847=141
→ Difference = (987-141) = 846
Physics Department:
→ Appeared = (14/100) * 5484 = 768
→ Cleared = (42/360)* 847=99
→ Difference = (768-99) = 669
Chemistry Department:
→ Appeared = (11/100) * 5484 = 603
→ Cleared = (31/360)* 847= 73
→ Difference = (603-73) = 530 (ans)
Commerce Department:
→ Appeared = (23/100) * 5484 = 1261
→ Cleared = (72/360)* 847= 169
→ Difference = (1261-169) = 1092
Other Departments:
→ Appeared = (7/100) * 5484 = 384
→ Cleared = (67/360)* 847= 158
→ Difference = (384-158) =226

10. Option B
→ No. of students not cleared= (5484 -847) = 4637
→ % of students not cleared = (4637/5484) *100 = 84.55 %
(ans)

11. Ans. D.
Solution:
240000×19% – 144000×15%
=45600-21600
=24000

12. Ans. C.
Solution:
Income of A and B: Expenditure of E and F
240000×(15+20)%:144000×(20+18)%
240000×35%:144000×38%
240×35:144×38
8400:5472
175:114

13. Ans. E.
Solution:
Saving = Income-Expenditure
=240000×(20+18)% – 144000×(17+17)%
=240000×38% – 144000×34%
=91200-48960
=42240

14. Ans. A.
Solution:
240000×(15+12+18)%/3
=240000×45%/3
=36000

15. Ans. C.
Solution:
Now the income of F= 240000×19%×110/100 =50160
The expenditure of F= 144000×20%×105% =30240
Saving= 50160-30240 =19920