Home / Solution to the quiz

Solution to the quiz

150+ RRB NTPC Previous Solved Papers PDF  Free Download Now
RRB NTPC Free Study Material PDF Free Download Now
RRB NTPC Free Mock Test Attempt It Now
Quant Booster eBook – A Complete Maths Shortcut eBook   GET Book Now
SSC CGL,CPO,GD 2018 Study Material & Book Free PDF Free Download Now

 

Print Friendly, PDF & Email

Q1 Option A

 

 

 

 

 

 

 

 

The man firstly faces the direction OA. On moving 45 degree clockwise[Please check carefully always if clockwise or anticlockwise], he faces the direction OB.
Now again he moved 180 degree clockwise, now he will be facing OC. From here he moved 270 degree anticlockwise, Finally he is facing OD, which is South west.

Q2. Option D

 

 

 

 

 

 

 

 

The man firstly faces the direction OA. On moving 45 degree clockwise, he faces the direction OB.
Now again he moved 180 degree clockwise, now he will be facing OC. From here he moved 45 degree anticlockwise, Finally he is facing OD, which is South direction.

Q3. Option B

 

 

 

 

 

Raviraj starts from home at A, moves 20 Km in south upto B. Then he turns right and moves 10 Km upto C, then he turns right and moves 20 Km upto D, then he turns lefts and moves 20 Km upto E.
So from image it is clear that, if he moves straight then he will have to move AD+DE, AD = BC = 10 Km
So, he will have to move 10 + 20 = 30 Km

Q4. Option C

 

 

 

 

 

 

 

Clearly, the child moves from A to B 90 metres eastwards upto B, then turns right and moves 20 metre upto C, then turns right and moves upto 30 metre upto D. Finally he turns right and moves upto 100 metre upto E.
So AB = 90 metre, BF = CD = 30 metre,
So, AF = AB – BF = 60 metre

Also DE = 100 metre, DF = BC = 20 metre
So, EF = DE – DF = 80 metre
as we can see in image that triangle AFE is a right angled triangle and we are having two sides, need to calculate third one, so we can apply Pythagoras theorem here
A=AE=√(〖AF〗^2+〖EF〗^2 )
=√(〖60〗^2+〖80〗^2 )
=√(3600+6400)
=√10000
=1000
So from starting point his father was 100 metre away.

Q5 Option D

 

 

 

 

 

 

 

Clearly, Kunal moves from A 10 Km northwards upto B, then moves 6 Km southwards upto C, turns towards east and moves 3 km upto D.
Then AC = (AB-BC) = 4 Km

So Kunal distance from starting point A
AD= √(AC^2+CD^2 )
= √(4^2+3^2 )
=√25=5
So AD is 5 Km also with reference to starting point Kunal’s direction is North-East.

Q6. Option C

 

 

 

 

 

Now, Gaurav distance from his initial position A to E

AE = (AD+DE) = 40 + 20 = 60 metres.

Q7. Option B

 

 

 

 

Now dog is facing North

Q8. Option A

 

 

 

 

 

Final direction will be north-east with reference to the starting position.

Q9. Option C

 

 

 

 

 

 

The movements of Rohit are shown in figure.
Rohit’s distance from the starting point A will be
AE = AD+DE = 20 + 15 = 35 metre

And direction with reference to the starting point is east.

Q10. Option B

 

 

 

 

 

 

Distance from the P to Q is 10 metres and direction of Q with reference to to P is west.

GovernmentAdda Recommends  Online Tyari Mock Test
RRB Group D Speed Test Attempt Now Attempt Now
Railway RRB Pshyco Complete Package  Get It Now
SSC CHSL, CGL Mock Test (1 free+30 Paid) Attempt Now

 

RRB JE Free Study Material PDF Books Free Download Now
FCI Free Study Material PDF Books Free Download Now
SSC JE Free Study Material PDF Books Free Download Now
Download Quant Power Bank (1000+ Pages) Free Download Now
Reasoning & GI Booster -Power Bank Book (1200+ Pages) Free Download Now

 

error: