SSC CGL Study Material Book Free PDF >> Download Now
|Quant Booster – A Complete Maths Shortcut Book (850+ Pages)||Get Now|
|Download Reasoning General Intelligence Power Book (1200+ Pages)||Free Download Now|
Q1. Option A
In the two statements given in I, the common words are ‘But’, ‘None’, ‘And’ and thecommon code words are ‘Ne’, ‘Pa’, ,’Lo’. So, ‘Ne’, ‘Pa’ and ‘Lo’ are codes for ‘But’, ‘None’ and ‘And’. Thus, in the first statement, ‘Sic’ is the code for ‘No’.
Q2. Option E
From I, we have: M > V > Q.From II, we have: T > Q, T > M, P > T.Combining the above two, we have: P>T>M>V>Q i.e. Q<v<m<t<p.< p=””>Clearly, M is in the middle.
Q3. Option C
In the given statement and I, the common word is ‘good’ and the common code word is ‘co’. So, ‘co’ is the code for ‘good’.In the given statement and II, the common words are ‘He’ and ‘is’ and the common code words are ‘sin’ and ‘bye’. So ‘sin’ and ‘bye’ are the codes for ‘He’ and ‘is’. Thus, in the given statement, ‘co’ is the code for ‘good’.
Q4. Option D
In I and II, the common words are ‘me’ and ‘water’ and the common code numbers are ‘7’ and ‘1’. So, the code for ‘water’ is either ‘7’ or ‘1’.
Q5. Option D
From I and II, we find that maximum (243 x 3) i.e. 729 visitors saw the exhibition. But the exact number cannot be determined.
Q6. Option C
From I, we conclude that in a class of 47 students, Gaurav ranks 18th from the top and hence 30th from the last. From II, we conclude that there are 9 students above and 37 students below Jatin in rank. Thus, there are (9 + 1 + 37) = 47 students in the class.So, Gaurav who ranks 18th from the top, is 30th from the last.
Q7. Option C
From I, we conclude that P is 9th from the top. Thus, in a class of 30 students, P ranks 22nd from the bottom. From II, we conclude that P is 22nd from the bottom.
Q8. Option E
From I, we know that L is T’s brother and J’s husband. Since L is the only son of his parents, T is L’s sister. From II, we know that K is L’s daughter. Thus, from I and II, we conclude that T is the sister of K’s father i.e. T is K’s aunt.
Q9. Option B
From II, we know that P’s mother is married to J’s husband, which means that J is P’s mother.
Q10. Option C
From I, we conclude that Y is the child of D who is wife of X i.e. X is Y’s father.From II, X is married to Y’s father. This implies that X is Y’s mother.
|Download English Power Book (2000+ Pages)||Free Download Now|