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# Aptitude Questions – Quadratic Equations

130+ SSC CGL Previous Papers With Solution Free >>

Here we are creating sample questions in Quadratic Equations which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

1. x² – 32x + 252 = 0
y² – 28y + 192 = 0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be established
E. X = Y or relation cannot be established
Explanation:

x² – 32x + 252 = 0
x = 18, 14
y² – 28y + 192 = 0
y = 12, 16
2. x² – 32x + 247 = 0
y² – 22y + 117 = 0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be established
C. X ≥ Y
Explanation:

x² – 32x + 247 = 0
x = 13, 19
y² – 22y + 117 = 0
y = 13, 9
3. x² + 29x + 208 = 0
y² + 19y + 78 = 0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be established
D. X ≤ Y
Explanation:

x² + 29x + 208 = 0
x = -13, -16
y² + 19y + 78 = 0
y = -13, -6
4. x² – 22x + 105 = 0
y² – 27y + 162 = 0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be established
E. X = Y or relation cannot be established
Explanation:

x² – 22x + 105 = 0
x = 15, 7
y² – 27y + 162 = 0
y = 18, 9
5. (x – 18)² = 0
y² = 324
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be established
C. X ≥ Y
Explanation:

x² – 36x + 324 = 0
x = 18, 18
y² = 324
y = ±18
6. x² – 41x + 400 = 0
y² – 29y + 210 = 0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be established
A. X > Y
Explanation:

x² – 41x + 400 = 0
x = 25, 16
y² – 29y + 210 = 0
y = 14, 15
7. x² – 25x + 156 = 0
y² – 32y + 255 = 0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be established
B. X < Y
Explanation:

x² – 25x + 156 = 0
x = 12, 13
y² – 32y + 255 = 0
y = 15, 17
8. x² – 35x + 294 = 0
y² – 23y + 132 = 0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be established
A. X > Y
Explanation:

x² – 35x + 294 = 0
x = 21, 14
y² – 23y + 132 = 0
y = 11, 12
9. x² = 64
y² – 34y + 289 = 0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be established
B. X < Y
Explanation:

x² = 64
x = 8, – 8
y² – 34y + 289 = 0
y = 17, 17
10. x² – 29x + 208 = 0
y² – 32y + 255 = 0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be established
E. X = Y or relation cannot be established
Explanation:

x² – 29x + 208 = 0
x = 13, 16
y² – 32y + 255 = 0
y = 15, 17